What is the general solution for cos(2y)-sin(2y)=0 ?

The general solution for cos(2y)-sin(2y)=0 is y= pi/8+(pin)/2

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cos(2y)-sin(2y)=0

cos (2 y) - sin (2 y) = 0

y = \frac{π}{8} + \frac{πn}{2}

Solution steps

cos (2 y) - sin (2 y) = 0

Rewrite using trig identities

1 - tan (2 y) = 0

Move

1

to the right side

- tan (2 y) = - 1

Divide both sides by

- 1

tan (2 y) = 1

General solutions for

tan (2 y) = 1

2 y = \frac{π}{4} + πn

Solve

2 y = \frac{π}{4} + πn : y = \frac{π}{8} + \frac{πn}{2}

y = \frac{π}{8} + \frac{πn}{2}

sec (\frac{2 π}{3} + x) = 2

sin (t) = \frac{7}{9}, sin (2 t)

\frac{8}{17} = sin (2 x)

sec (2 x) + tan (2 x) = 2

sec (2 x) + tan (2 x) = 9

What is the general solution for cos(2y)-sin(2y)=0 ?
The general solution for cos(2y)-sin(2y)=0 is y= pi/8+(pin)/2