What is the general solution for 12sin(x)-sqrt(2)=sqrt(2)+8sin(x) ?

The general solution for 12sin(x)-sqrt(2)=sqrt(2)+8sin(x) is x= pi/4+2pin,x=(3pi)/4+2pin

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12sin(x)-sqrt(2)=sqrt(2)+8sin(x)

12 sin (x) - 2 = 2 + 8 sin (x)

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

Solution steps

12 sin (x) - 2 = 2 + 8 sin (x)

Solve by substitution

sin (x) = \frac{2}{2}

sin (x) = \frac{2}{2} : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

Combine all the solutions

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

cos (2 x + 30) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

tan (θ) = \frac{43}{90}

2 sin (2 x + \frac{π}{3}) = 1

sec (x) = 2, cos (x)

- cosh (sech (x)) (sech (x) tanh (x)) = 0

What is the general solution for 12sin(x)-sqrt(2)=sqrt(2)+8sin(x) ?
The general solution for 12sin(x)-sqrt(2)=sqrt(2)+8sin(x) is x= pi/4+2pin,x=(3pi)/4+2pin