What is the general solution for 2cos^2(x)+sin(x)=5 ?

The general solution for 2cos^2(x)+sin(x)=5 is No Solution for x\in\mathbb{R}

Popular >

2cos^2(x)+sin(x)=5

2 cos^{2} (x) + sin (x) = 5

No Solution for x \in R

Solution steps

2 cos^{2} (x) + sin (x) = 5

Subtract

5

from both sides

2 cos^{2} (x) + sin (x) - 5 = 0

Rewrite using trig identities

- 3 + sin (x) - 2 sin^{2} (x) = 0

Solve by substitution

sin (x) = \frac{1}{4} - i \frac{23}{4}, sin (x) = \frac{1}{4} + i \frac{23}{4}

sin (x) = \frac{1}{4} - i \frac{23}{4} :

No Solution

sin (x) = \frac{1}{4} + i \frac{23}{4} :

No Solution

Combine all the solutions

No Solution for x \in R

x, Y = 0.5 sin (3.07 x - 2.4 t + 0.59)

\frac{( 1 + tan ( x ) )}{sec ( x )} = 2, x

sin (x - 3 0^{\circ}) cos (x - 3 0^{\circ}) = \frac{3}{4}

cos (θ) = - \frac{7}{15}, cos (\frac{θ}{2}), 18 0^{\circ} < θ < 27 0^{\circ}

tan (x) + 2 = 0

What is the general solution for 2cos^2(x)+sin(x)=5 ?
The general solution for 2cos^2(x)+sin(x)=5 is No Solution for x\in\mathbb{R}