What is the general solution for -2cos(θ-1)=0.5 ?

The general solution for -2cos(θ-1)=0.5 is θ=1.82347…+2pin+1,θ=-1.82347…+2pin+1

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-2cos(θ-1)=0.5

- 2 cos (θ - 1) = 0.5

θ = 1.82347 \dots + 2 πn + 1, θ = - 1.82347 \dots + 2 πn + 1

Solution steps

- 2 cos (θ - 1) = 0.5

Divide both sides by

- 2

cos (θ - 1) = - 0.25

Apply trig inverse properties

θ - 1 = arccos (- 0.25) + 2 πn, θ - 1 = - arccos (- 0.25) + 2 πn

Solve

θ - 1 = arccos (- 0.25) + 2 πn : θ = arccos (- 0.25) + 2 πn + 1

Solve

θ - 1 = - arccos (- 0.25) + 2 πn : θ = - arccos (- 0.25) + 2 πn + 1

θ = arccos (- 0.25) + 2 πn + 1, θ = - arccos (- 0.25) + 2 πn + 1

Show solutions in decimal form

θ = 1.82347 \dots + 2 πn + 1, θ = - 1.82347 \dots + 2 πn + 1

cos (θ) = \frac{1}{9}

- 33 sin (v) + 3 cos (v) = 32

x, - arctan (y) = arctan (x)

cot (x) = tan^{2} (x)

sin (x + b) = cos (x)

What is the general solution for -2cos(θ-1)=0.5 ?
The general solution for -2cos(θ-1)=0.5 is θ=1.82347…+2pin+1,θ=-1.82347…+2pin+1