What is the general solution for 1+cot^2(θ)=1.33 ?

The general solution for 1+cot^2(θ)=1.33 is θ=1.04937…+pin,θ=2.09222…+pin

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1+cot^2(θ)=1.33

1 + cot^{2} (θ) = 1.33

θ = 1.04937 \dots + πn, θ = 2.09222 \dots + πn

Solution steps

1 + cot^{2} (θ) = 1.33

Solve by substitution

cot (θ) = 0.33, cot (θ) = - 0.33

cot (θ) = 0.33 : θ = arccot (0.33) + πn

cot (θ) = - 0.33 : θ = arccot (- 0.33) + πn

Combine all the solutions

θ = arccot (0.33) + πn, θ = arccot (- 0.33) + πn

Show solutions in decimal form

θ = 1.04937 \dots + πn, θ = 2.09222 \dots + πn

x, r + s - 6 t = cos (2 x + y)

cos (x) + cos^{3} (x) = 0

- 2 cos (\frac{θ}{2}) = 0

cos (x) = - \frac{3}{4}, tan (x) i s

cos (θ) = \frac{- 1}{3}

What is the general solution for 1+cot^2(θ)=1.33 ?
The general solution for 1+cot^2(θ)=1.33 is θ=1.04937…+pin,θ=2.09222…+pin