What is the general solution for sin(θ)=-1/8 ?

The general solution for sin(θ)=-1/8 is θ=-0.12532…+2pin,θ=pi+0.12532…+2pin

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sin(θ)=-1/8

sin (θ) = - \frac{1}{8}

θ = - 0.12532 \dots + 2 πn, θ = π + 0.12532 \dots + 2 πn

Solution steps

sin (θ) = - \frac{1}{8}

Apply trig inverse properties

θ = arcsin (- \frac{1}{8}) + 2 πn, θ = π + arcsin (\frac{1}{8}) + 2 πn

Show solutions in decimal form

θ = - 0.12532 \dots + 2 πn, θ = π + 0.12532 \dots + 2 πn

0 = 2 cos^{2} (θ) - cos (θ) - 1

sin (x) = \frac{3}{1.65}

tan (x) = - 2, tan (- x)

x, y^{1} = y sin (x)

- 0.3 cos (θ) = cos (2.2 + θ)

What is the general solution for sin(θ)=-1/8 ?
The general solution for sin(θ)=-1/8 is θ=-0.12532…+2pin,θ=pi+0.12532…+2pin