What is the general solution for -3(sin^2(θ)-cos^2(θ))=0 ?

The general solution for -3(sin^2(θ)-cos^2(θ))=0 is θ= pi/4+pin,θ=(3pi)/4+pin

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-3(sin^2(θ)-cos^2(θ))=0

- 3 (sin^{2} (θ) - cos^{2} (θ)) = 0

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

- 3 (sin^{2} (θ) - cos^{2} (θ)) = 0

Rewrite using trig identities

- 3 (- cos (2 θ)) = 0

Divide both sides by

- 3

- cos (2 θ) = 0

Divide both sides by

- 1

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

cos^{2} (t) - sin^{2} (t) = - 1

- a^{2} c_{1} cos (a x) - a^{2} c_{2} sin (a x) = 0

10 = - 12 sin (x) + 1.8 cos (x)

8 tan (B) + 12 = 3 tan (B) + 7

- 2 + sin (2 θ) = - \frac{3}{2}

What is the general solution for -3(sin^2(θ)-cos^2(θ))=0 ?
The general solution for -3(sin^2(θ)-cos^2(θ))=0 is θ= pi/4+pin,θ=(3pi)/4+pin