What is the general solution for 8tan(B)+12=3tan(B)+7 ?

The general solution for 8tan(B)+12=3tan(B)+7 is B=(3pi)/4+pin

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8tan(B)+12=3tan(B)+7

8 tan (B) + 12 = 3 tan (B) + 7

B = \frac{3 π}{4} + πn

Solution steps

8 tan (B) + 12 = 3 tan (B) + 7

Solve by substitution

tan (B) = - 1

tan (B) = - 1 : B = \frac{3 π}{4} + πn

Combine all the solutions

B = \frac{3 π}{4} + πn

- 2 + sin (2 θ) = - \frac{3}{2}

tan (c) = \frac{24}{7}

sin (t) = \frac{- 1}{2}

sin (x + \frac{π}{6}) + cos (x + \frac{π}{3}) = cos (2 x)

24 sin (2 t) - 24 cos (t) = 0

What is the general solution for 8tan(B)+12=3tan(B)+7 ?
The general solution for 8tan(B)+12=3tan(B)+7 is B=(3pi)/4+pin