What is the general solution for 2*9.19*sin(x)=1.5406 ?

The general solution for 2*9.19*sin(x)=1.5406 is x=0.08391…+2pin,x=pi-0.08391…+2pin

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29.19sin(x)=1.5406

2 \cdot 9.19 \cdot sin (x) = 1.5406

x = 0.08391 \dots + 2 πn, x = π - 0.08391 \dots + 2 πn

Degrees

x = 4.80813 \dots^{\circ} + 36 0^{\circ} n, x = 175.19186 \dots^{\circ} + 36 0^{\circ} n

Solution steps

2 \cdot 9.19 sin (x) = 1.5406

Divide both sides by

18.38

2 \cdot 9.19 sin (x) = 1.5406

Divide both sides by

18.38

\frac{2 \cdot 9.19 sin ( x )}{18.38} = \frac{1.5406}{18.38}

Simplify

sin (x) = \frac{1.5406}{18.38}

sin (x) = \frac{1.5406}{18.38}

Apply trig inverse properties

sin (x) = \frac{1.5406}{18.38}

General solutions for

sin (x) = \frac{1.5406}{18.38}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{1.5406}{18.38}) + 2 πn, x = π - arcsin (\frac{1.5406}{18.38}) + 2 πn

x = arcsin (\frac{1.5406}{18.38}) + 2 πn, x = π - arcsin (\frac{1.5406}{18.38}) + 2 πn

Show solutions in decimal form

x = 0.08391 \dots + 2 πn, x = π - 0.08391 \dots + 2 πn

csc^{3} (x) - 4 csc (x) = 3 cot^{2} (x)

1 + tan^{2} (θ) = 4 tan^{2} (θ)

(tan (θ) + 1) (cos (θ) + 1) (sin (θ)) = 0

6 sin (2 x) - 3 = 0

4 cos^{2} (x) - sin (x) = 1

What is the general solution for 2*9.19*sin(x)=1.5406 ?
The general solution for 2*9.19*sin(x)=1.5406 is x=0.08391…+2pin,x=pi-0.08391…+2pin