What is the general solution for (tan(θ)+1)(cos(θ)+1)(sin(θ))=0 ?

The general solution for (tan(θ)+1)(cos(θ)+1)(sin(θ))=0 is θ=(3pi)/4+pin,θ=pi+2pin,θ=2pin

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(tan(θ)+1)(cos(θ)+1)(sin(θ))=0

(tan (θ) + 1) (cos (θ) + 1) (sin (θ)) = 0

θ = \frac{3 π}{4} + πn, θ = π + 2 πn, θ = 2 πn

Solution steps

(tan (θ) + 1) (cos (θ) + 1) (sin (θ)) = 0

Solving each part separately

tan (θ) + 1 = 0 or cos (θ) + 1 = 0 or sin (θ) = 0

tan (θ) + 1 = 0 : θ = \frac{3 π}{4} + πn

cos (θ) + 1 = 0 : θ = π + 2 πn

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = \frac{3 π}{4} + πn, θ = π + 2 πn, θ = 2 πn

6 sin (2 x) - 3 = 0

4 cos^{2} (x) - sin (x) = 1

0.6 = cos (4 x)

sin (x) = \frac{1}{1.33}

- 3 = cos (0 + C)

What is the general solution for (tan(θ)+1)(cos(θ)+1)(sin(θ))=0 ?
The general solution for (tan(θ)+1)(cos(θ)+1)(sin(θ))=0 is θ=(3pi)/4+pin,θ=pi+2pin,θ=2pin