What is the general solution for arccos(x)=arcsin(9/41) ?

The general solution for arccos(x)=arcsin(9/41) is x= 40/41

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arccos(x)=arcsin(9/41)

arccos (x) = arcsin (\frac{9}{41})

x = \frac{40}{41}

Solution steps

arccos (x) = arcsin (\frac{9}{41})

Apply trig inverse properties

x = \frac{40}{41}

x, - y sin (x) = 0

2 sin (\frac{x}{2} + \frac{π}{3}) = 3

x, 4 sin^{4} (x) - 8 sin^{2} (x) + 3 = 0

3 + 3 sin (θ) = 3 - 3 sin (θ)

\frac{sin ( C )}{18} = \frac{sin ( 6 3 ^{\circ} )}{17}

What is the general solution for arccos(x)=arcsin(9/41) ?
The general solution for arccos(x)=arcsin(9/41) is x= 40/41