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Popular >

2sin^2(θ)-sqrt(2)sin(θ)=0

Solution

2 sin^{2} (θ) - 2 sin (θ) = 0

Solution

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn, θ = 2 πn, θ = π + 2 πn

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Solution steps

2 sin^{2} (θ) - 2 sin (θ) = 0

Solve by substitution

sin (θ) = \frac{2}{2}, sin (θ) = 0

sin (θ) = \frac{2}{2} : θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn, θ = 2 πn, θ = π + 2 πn

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6sec^2(x)+tan(x)-9=0

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Frequently Asked Questions (FAQ)

What is the general solution for 2sin^2(θ)-sqrt(2)sin(θ)=0 ?
The general solution for 2sin^2(θ)-sqrt(2)sin(θ)=0 is θ= pi/4+2pin,θ=(3pi)/4+2pin,θ=2pin,θ=pi+2pin