What is (4i+3)(5-2i) ?

The solution to (4i+3)(5-2i) is 23+14i

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simplify (4i+3)(5-2i)

simplify

(4 i + 3) (5 - 2 i)

23 + 14 i

Solution steps

(4 i + 3) (5 - 2 i)

Rewrite

4 i + 3

in standard complex form:

3 + 4 i

= (3 + 4 i) (5 - 2 i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= (3 \cdot 5 - 4 (- 2)) + (3 (- 2) + 4 \cdot 5) i

Simplify

(3 \cdot 5 - 4 (- 2)) + (3 (- 2) + 4 \cdot 5) i : 23 + 14 i

= 23 + 14 i

4 (x + 2)^{2} = 4

\frac{5}{a ^{2} + 3 a + 2} + \frac{5 a + 1}{a ^{2} + 3 a + 2}

18 \leq 3 (b - 4)

- 4 (\frac{x + 1}{4}) > x - 8 (\frac{2}{3 - x})

- y^{2} + yz - x y