What is ln(x)-[ln(x+1)+ln(x-1)] ?

The solution to ln(x)-[ln(x+1)+ln(x-1)] is ln(x)-ln((x+1)(x-1))

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simplify ln(x)-[ln(x+1)+ln(x-1)]

simplify

ln (x) - [ln (x + 1) + ln (x - 1)]

ln (x) - ln ((x + 1) (x - 1))

Solution steps

ln (x) - [ln (x + 1) + ln (x - 1)]

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (x + 1) + ln (x - 1) = ln ((x + 1) (x - 1))

= ln (x) - [ln ((x + 1) (x - 1))]

Remove parentheses:

(a) = a

= ln (x) - ln ((x + 1) (x - 1))

lo g_{b} (x) + lo g_{b} (y) - lo g_{b} (u)

\frac{1}{2} lo g_{b} (x) + 5 lo g_{b} (y) - 4 lo g_{b} (x)

lo g_{3} (x y)

f (s) = ln (\frac{s ^{2} + 9}{s ^{2} + 64})

10 lo g_{10} (1.6 \cdot 1 0^{- 5}) + 120

What is ln(x)-[ln(x+1)+ln(x-1)] ?
The solution to ln(x)-[ln(x+1)+ln(x-1)] is ln(x)-ln((x+1)(x-1))