What are the solutions to the equation 0.2x^2-0.4x-2.1=0 ?

The solutions to the equation 0.2x^2-0.4x-2.1=0 are x=(2+sqrt(46))/2 ,x=(2-sqrt(46))/2

Find the zeros of 0.2x^2-0.4x-2.1=0

The zeros of 0.2x^2-0.4x-2.1=0 are x=(2+sqrt(46))/2 ,x=(2-sqrt(46))/2

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0.2 x^{2} - 0.4 x - 2.1 = 0

x = \frac{2 + 46}{2}, x = \frac{2 - 46}{2}

Decimal Notation

x = 4.39116 \dots, x = - 2.39116 \dots

Solution steps

0.2 x^{2} - 0.4 x - 2.1 = 0

Multiply both sides by

10

2 x^{2} - 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 21) = 246

x_{1, 2} = \frac{- ( - 4 ) \pm 2 46}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 46}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 46}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 46}{2 \cdot 2} : \frac{2 + 46}{2}

x = \frac{- ( - 4 ) - 2 46}{2 \cdot 2} : \frac{2 - 46}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 46}{2}, x = \frac{2 - 46}{2}

6 x^{2} + 11 b x = 10 b^{2}

- 2 x^{2} + 23 = 7

4 x^{2} = - 4 x - 17

s^{2} + 2 s + 5

- 3 x^{2} + 12 = 0

What are the solutions to the equation 0.2x^2-0.4x-2.1=0 ?
The solutions to the equation 0.2x^2-0.4x-2.1=0 are x=(2+sqrt(46))/2 ,x=(2-sqrt(46))/2
Find the zeros of 0.2x^2-0.4x-2.1=0
The zeros of 0.2x^2-0.4x-2.1=0 are x=(2+sqrt(46))/2 ,x=(2-sqrt(46))/2