What are the solutions to the equation 2(x+3)^2-47=11 ?

The solutions to the equation 2(x+3)^2-47=11 are x=sqrt(29)-3,x=-sqrt(29)-3

Find the zeros of 2(x+3)^2-47=11

The zeros of 2(x+3)^2-47=11 are x=sqrt(29)-3,x=-sqrt(29)-3

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2 (x + 3)^{2} - 47 = 11

x = 29 - 3, x = - 29 - 3

Decimal Notation

x = 2.38516 \dots, x = - 8.38516 \dots

Solution steps

2 (x + 3)^{2} - 47 = 11

Move

47

to the right side

2 (x + 3)^{2} = 58

Divide both sides by

2

(x + 3)^{2} = 29

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 29 : x = 29 - 3

Solve

x + 3 = - 29 : x = - 29 - 3

The solutions to the quadratic equation are:

x = 29 - 3, x = - 29 - 3

- x^{2} + 8 x + 75 = 13

2 x^{2} + 7 x + 23 = 20

4 x^{2} + 28 = 5 x^{2} + 76

4 x^{2} + 12 x = 135

x^{2} + 37 = - 14 x

What are the solutions to the equation 2(x+3)^2-47=11 ?
The solutions to the equation 2(x+3)^2-47=11 are x=sqrt(29)-3,x=-sqrt(29)-3
Find the zeros of 2(x+3)^2-47=11
The zeros of 2(x+3)^2-47=11 are x=sqrt(29)-3,x=-sqrt(29)-3