What are the solutions to the equation 4x^2+28=5x^2+76 ?

The solutions to the equation 4x^2+28=5x^2+76 are x=4sqrt(3)i,x=-4sqrt(3)i

Find the zeros of 4x^2+28=5x^2+76

The zeros of 4x^2+28=5x^2+76 are x=4sqrt(3)i,x=-4sqrt(3)i

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4 x^{2} + 28 = 5 x^{2} + 76

x = 43 i, x = - 43 i

Solution steps

4 x^{2} + 28 = 5 x^{2} + 76

Move

28

to the right side

4 x^{2} = 5 x^{2} + 48

Move

5 x^{2}

to the left side

- x^{2} = 48

Divide both sides by

- 1

x^{2} = - 48

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 48, x = - - 48

- 48 = 43 i

- - 48 = - 43 i

x = 43 i, x = - 43 i

4 x^{2} + 12 x = 135

x^{2} + 37 = - 14 x

m^{2} + 10 m + 21 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 18 x

What are the solutions to the equation 4x^2+28=5x^2+76 ?
The solutions to the equation 4x^2+28=5x^2+76 are x=4sqrt(3)i,x=-4sqrt(3)i
Find the zeros of 4x^2+28=5x^2+76
The zeros of 4x^2+28=5x^2+76 are x=4sqrt(3)i,x=-4sqrt(3)i