What are the solutions to the equation (5x+1)^2-16=0 ?

The solutions to the equation (5x+1)^2-16=0 are x= 3/5 ,x=-1

Find the zeros of (5x+1)^2-16=0

The zeros of (5x+1)^2-16=0 are x= 3/5 ,x=-1

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(5 x + 1)^{2} - 16 = 0

x = \frac{3}{5}, x = - 1

Decimal Notation

x = 0.6, x = - 1

Solution steps

(5 x + 1)^{2} - 16 = 0

Move

16

to the right side

(5 x + 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 1 = 16 : x = \frac{3}{5}

Solve

5 x + 1 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - 1

2 (x + 2)^{2} - 23 = - 17

z^{2} = - 1

x^{2} = 5^{2} + 1 2^{2}

x^{2} - 289 = 0

4 (x + 7)^{2} - 49 = - 13

What are the solutions to the equation (5x+1)^2-16=0 ?
The solutions to the equation (5x+1)^2-16=0 are x= 3/5 ,x=-1
Find the zeros of (5x+1)^2-16=0
The zeros of (5x+1)^2-16=0 are x= 3/5 ,x=-1