What are the solutions to the equation x^2+61=1-17x ?

The solutions to the equation x^2+61=1-17x are x=-5,x=-12

Find the zeros of x^2+61=1-17x

The zeros of x^2+61=1-17x are x=-5,x=-12

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x^{2} + 61 = 1 - 17 x

x = - 5, x = - 12

Solution steps

x^{2} + 61 = 1 - 17 x

Move

17 x

to the left side

x^{2} + 61 + 17 x = 1

Move

1

to the left side

x^{2} + 17 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 60 = 7

x_{1, 2} = \frac{- 17 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 7}{2 \cdot 1}, x_{2} = \frac{- 17 - 7}{2 \cdot 1}

x = \frac{- 17 + 7}{2 \cdot 1} : - 5

x = \frac{- 17 - 7}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = - 5, x = - 12

(2 x + 3) (2 x - 3) = 0

x, x^{2} - x y + y^{2} = 7

- 7 x^{2} + 17 x + 12 = 0

4 - 2 a^{2} = - 7

x, 8 x^{2} - 6 y^{2} - 16 x + 24 y - 16 = 0

What are the solutions to the equation x^2+61=1-17x ?
The solutions to the equation x^2+61=1-17x are x=-5,x=-12
Find the zeros of x^2+61=1-17x
The zeros of x^2+61=1-17x are x=-5,x=-12