What are the solutions to the equation x^2+5x-104=0 ?

The solutions to the equation x^2+5x-104=0 are x=8,x=-13

Find the zeros of x^2+5x-104=0

The zeros of x^2+5x-104=0 are x=8,x=-13

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x^{2} + 5 x - 104 = 0

x = 8, x = - 13

Solution steps

x^{2} + 5 x - 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 104 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 104) = 21

x_{1, 2} = \frac{- 5 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 21}{2 \cdot 1}, x_{2} = \frac{- 5 - 21}{2 \cdot 1}

x = \frac{- 5 + 21}{2 \cdot 1} : 8

x = \frac{- 5 - 21}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 8, x = - 13

8 - \frac{( x + 4 ) ( x - 8 )}{3} = - 2 x

5 x^{2} + 70 x - 1355 = 0

x^{2} + 12 x + 36 = 100

x^{2} + 4 x - 7

24 = x^{2} - 4 x + 3

What are the solutions to the equation x^2+5x-104=0 ?
The solutions to the equation x^2+5x-104=0 are x=8,x=-13
Find the zeros of x^2+5x-104=0
The zeros of x^2+5x-104=0 are x=8,x=-13