What are the solutions to the equation 3(x+4)^2-3(x-6)=36 ?

The solutions to the equation 3(x+4)^2-3(x-6)=36 are x=-2,x=-5

Find the zeros of 3(x+4)^2-3(x-6)=36

The zeros of 3(x+4)^2-3(x-6)=36 are x=-2,x=-5

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3 (x + 4)^{2} - 3 (x - 6) = 36

x = - 2, x = - 5

Solution steps

3 (x + 4)^{2} - 3 (x - 6) = 36

Expand

3 (x + 4)^{2} - 3 (x - 6) : 3 x^{2} + 21 x + 66

3 x^{2} + 21 x + 66 = 36

Move

36

to the left side

3 x^{2} + 21 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 3 \cdot 30}{2 \cdot 3}

2 1^{2} - 4 \cdot 3 \cdot 30 = 9

x_{1, 2} = \frac{- 21 \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 21 + 9}{2 \cdot 3}, x_{2} = \frac{- 21 - 9}{2 \cdot 3}

x = \frac{- 21 + 9}{2 \cdot 3} : - 2

x = \frac{- 21 - 9}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

6 x^{2} - 12 x + 6 = 0

9 n^{2} + 10 = 91

5 x^{2} + 15 = 17 x

2 x^{2} - 2 x + 6 = 0

θ^{2} + 54 = 90

What are the solutions to the equation 3(x+4)^2-3(x-6)=36 ?
The solutions to the equation 3(x+4)^2-3(x-6)=36 are x=-2,x=-5
Find the zeros of 3(x+4)^2-3(x-6)=36
The zeros of 3(x+4)^2-3(x-6)=36 are x=-2,x=-5