What are the solutions to the equation 8x^2+14x+40=7x^2 ?

The solutions to the equation 8x^2+14x+40=7x^2 are x=-4,x=-10

Find the zeros of 8x^2+14x+40=7x^2

The zeros of 8x^2+14x+40=7x^2 are x=-4,x=-10

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8 x^{2} + 14 x + 40 = 7 x^{2}

x = - 4, x = - 10

Solution steps

8 x^{2} + 14 x + 40 = 7 x^{2}

Move

7 x^{2}

to the left side

x^{2} + 14 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 40 = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 6}{2 \cdot 1}

x = \frac{- 14 + 6}{2 \cdot 1} : - 4

x = \frac{- 14 - 6}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 4, x = - 10

x^{2} + 2 a x + a^{2} = 0

- x^{2} + 6 x - 8

(9 z + \frac{1}{2})^{2} + 61 = 39

- 40 m^{2} + 10 m - 1 = 0

m^{2} - 11 m + 30 = 0

What are the solutions to the equation 8x^2+14x+40=7x^2 ?
The solutions to the equation 8x^2+14x+40=7x^2 are x=-4,x=-10
Find the zeros of 8x^2+14x+40=7x^2
The zeros of 8x^2+14x+40=7x^2 are x=-4,x=-10