What are the solutions to the equation (x+1)(x-5)=0 ?

The solutions to the equation (x+1)(x-5)=0 are x=-1,x=5

Find the zeros of (x+1)(x-5)=0

The zeros of (x+1)(x-5)=0 are x=-1,x=5

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(x + 1) (x - 5) = 0

x = - 1, x = 5

Solution steps

(x + 1) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = - 1, x = 5

(x + 1)^{2} = 3

3 x^{2} - 5 = 13

6 x^{2} - 2 x + 3 = 0

3 x^{2} + 3 x - 7 = 0

x^{2} - 5 = 44

What are the solutions to the equation (x+1)(x-5)=0 ?
The solutions to the equation (x+1)(x-5)=0 are x=-1,x=5
Find the zeros of (x+1)(x-5)=0
The zeros of (x+1)(x-5)=0 are x=-1,x=5