What are the solutions to the equation 7k=78-k^2 ?

The solutions to the equation 7k=78-k^2 are k=-13,k=6

Find the zeros of 7k=78-k^2

The zeros of 7k=78-k^2 are k=-13,k=6

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7 k = 78 - k^{2}

k = - 13, k = 6

Solution steps

7 k = 78 - k^{2}

Switch sides

78 - k^{2} = 7 k

Move

7 k

to the left side

78 - k^{2} - 7 k = 0

Write in the standard form

a x^{2} + b x + c = 0

- k^{2} - 7 k + 78 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 1 ) \cdot 78}{2 ( - 1 )}

(- 7)^{2} - 4 (- 1) \cdot 78 = 19

k_{1, 2} = \frac{- ( - 7 ) \pm 19}{2 ( - 1 )}

Separate the solutions

k_{1} = \frac{- ( - 7 ) + 19}{2 ( - 1 )}, k_{2} = \frac{- ( - 7 ) - 19}{2 ( - 1 )}

k = \frac{- ( - 7 ) + 19}{2 ( - 1 )} : - 13

k = \frac{- ( - 7 ) - 19}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

k = - 13, k = 6

12 x^{2} - 36 x = 0

x^{2} + x - 14 = 0

x^{2} + x - 16 = 0

3 (2 x + 4)^{2} - 48 = 30

x^{2} - 13 x - 36 = 0

What are the solutions to the equation 7k=78-k^2 ?
The solutions to the equation 7k=78-k^2 are k=-13,k=6
Find the zeros of 7k=78-k^2
The zeros of 7k=78-k^2 are k=-13,k=6