What are the solutions to the equation solvefor s,h(s)=-16s^2+80s ?

The solutions to the equation solvefor s,h(s)=-16s^2+80s are s=0,s=(80-h)/(16)

Find the zeros of solvefor s,h(s)=-16s^2+80s

The zeros of solvefor s,h(s)=-16s^2+80s are s=0,s=(80-h)/(16)

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solve for

s, h (s) = - 16 s^{2} + 80 s

s = 0, s = \frac{80 - h}{16}

Solution steps

h (s) = - 16 s^{2} + 80 s

Refine

s h = - 16 s^{2} + 80 s

Switch sides

- 16 s^{2} + 80 s = s h

Move

s h

to the left side

- 16 s^{2} + 80 s - s h = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 s^{2} + (80 - h) s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( 80 - h ) \pm ( 80 - h ) ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

Simplify

(80 - h)^{2} - 4 (- 16) \cdot 0 : - h + 80

s_{1, 2} = \frac{- ( 80 - h ) \pm ( - h + 80 )}{2 ( - 16 )}

Separate the solutions

s_{1} = \frac{- ( 80 - h ) - h + 80}{2 ( - 16 )}, s_{2} = \frac{- ( 80 - h ) - ( - h + 80 )}{2 ( - 16 )}

s = \frac{- ( 80 - h ) - h + 80}{2 ( - 16 )} : 0

s = \frac{- ( 80 - h ) - ( - h + 80 )}{2 ( - 16 )} : \frac{80 - h}{16}

The solutions to the quadratic equation are:

s = 0, s = \frac{80 - h}{16}

a = x^{2} - 18 x + 80

x^{2} + 8 x + 16 = 16

x, y = x^{2} - 2 x - 3

u^{2} - 4 u + 4 = 0

- 0.6 x^{2} + 14 x + 15 = - 0.4 x + 99

What are the solutions to the equation solvefor s,h(s)=-16s^2+80s ?
The solutions to the equation solvefor s,h(s)=-16s^2+80s are s=0,s=(80-h)/(16)
Find the zeros of solvefor s,h(s)=-16s^2+80s
The zeros of solvefor s,h(s)=-16s^2+80s are s=0,s=(80-h)/(16)