What are the solutions to the equation x^2=-4x-4 ?

The solutions to the equation x^2=-4x-4 are x=-2

Find the zeros of x^2=-4x-4

The zeros of x^2=-4x-4 are x=-2

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x^{2} = - 4 x - 4

x = - 2

Solution steps

x^{2} = - 4 x - 4

Move

4

to the left side

x^{2} + 4 = - 4 x

Move

4 x

to the left side

x^{2} + 4 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

x^{2} - 18 x + 10 = 0

x^{2} - 4 x + 24 = 0

x^{2} - 18 x + 401 = 0

(6 x - 4) (3 x + 5) = (4 x - 9) (3 x + 5)

x^{2} = \frac{4}{9}

What are the solutions to the equation x^2=-4x-4 ?
The solutions to the equation x^2=-4x-4 are x=-2
Find the zeros of x^2=-4x-4
The zeros of x^2=-4x-4 are x=-2