What are the solutions to the equation 12x^2+24x-6=0 ?

The solutions to the equation 12x^2+24x-6=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2

Find the zeros of 12x^2+24x-6=0

The zeros of 12x^2+24x-6=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2

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12 x^{2} + 24 x - 6 = 0

x = \frac{- 2 + 6}{2}, x = - \frac{2 + 6}{2}

Solution steps

12 x^{2} + 24 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

2 4^{2} - 4 \cdot 12 (- 6) = 126

x_{1, 2} = \frac{- 24 \pm 12 6}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 24 + 12 6}{2 \cdot 12}, x_{2} = \frac{- 24 - 12 6}{2 \cdot 12}

x = \frac{- 24 + 12 6}{2 \cdot 12} : \frac{- 2 + 6}{2}

x = \frac{- 24 - 12 6}{2 \cdot 12} : - \frac{2 + 6}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 6}{2}, x = - \frac{2 + 6}{2}

12 x^{2} - 13 x - 35 = 0

4 x^{2} - x + 6 = 0

- 12 x^{2} + 5 x + 2 = 0

- 8 x^{2} + 3 x - 7 = 0

2 x^{2} - 6 = 4 x

What are the solutions to the equation 12x^2+24x-6=0 ?
The solutions to the equation 12x^2+24x-6=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2
Find the zeros of 12x^2+24x-6=0
The zeros of 12x^2+24x-6=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2