What are the solutions to the equation (x+1)^2+9=0 ?

The solutions to the equation (x+1)^2+9=0 are x=3i-1,x=-3i-1

Find the zeros of (x+1)^2+9=0

The zeros of (x+1)^2+9=0 are x=3i-1,x=-3i-1

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(x + 1)^{2} + 9 = 0

x = 3 i - 1, x = - 3 i - 1

Solution steps

(x + 1)^{2} + 9 = 0

Move

9

to the right side

(x + 1)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 9 : x = 3 i - 1

Solve

x + 1 = - - 9 : x = - 3 i - 1

The solutions to the quadratic equation are:

x = 3 i - 1, x = - 3 i - 1

2 x^{2} + 18 x = 0

12 x^{2} - 6 x - 6 = 0

x^{2} - 30 x = 0

x^{2} + \frac{2}{5} x + 9

x^{2} + 22 x + 28 = 12 x

What are the solutions to the equation (x+1)^2+9=0 ?
The solutions to the equation (x+1)^2+9=0 are x=3i-1,x=-3i-1
Find the zeros of (x+1)^2+9=0
The zeros of (x+1)^2+9=0 are x=3i-1,x=-3i-1