What are the solutions to the equation 2x^2+18x=0 ?

The solutions to the equation 2x^2+18x=0 are x=0,x=-9

Find the zeros of 2x^2+18x=0

The zeros of 2x^2+18x=0 are x=0,x=-9

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2 x^{2} + 18 x = 0

x = 0, x = - 9

Solution steps

2 x^{2} + 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

1 8^{2} - 4 \cdot 2 \cdot 0 = 18

x_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 18 + 18}{2 \cdot 2}, x_{2} = \frac{- 18 - 18}{2 \cdot 2}

x = \frac{- 18 + 18}{2 \cdot 2} : 0

x = \frac{- 18 - 18}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

12 x^{2} - 6 x - 6 = 0

x^{2} - 30 x = 0

x^{2} + \frac{2}{5} x + 9

x^{2} + 22 x + 28 = 12 x

2 x^{2} - 5 x - 3 = 2 x - 4 x^{2}

What are the solutions to the equation 2x^2+18x=0 ?
The solutions to the equation 2x^2+18x=0 are x=0,x=-9
Find the zeros of 2x^2+18x=0
The zeros of 2x^2+18x=0 are x=0,x=-9