What are the solutions to the equation 3x^2+6x-2=-2 ?

The solutions to the equation 3x^2+6x-2=-2 are x=0,x=-2

Find the zeros of 3x^2+6x-2=-2

The zeros of 3x^2+6x-2=-2 are x=0,x=-2

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3 x^{2} + 6 x - 2 = - 2

x = 0, x = - 2

Solution steps

3 x^{2} + 6 x - 2 = - 2

Move

2

to the left side

3 x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 \cdot 3}, x_{2} = \frac{- 6 - 6}{2 \cdot 3}

x = \frac{- 6 + 6}{2 \cdot 3} : 0

x = \frac{- 6 - 6}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

12 x^{2} - 200 x + 600 = 0

x^{2} + 6 x - 3 = 0

x^{2} + 7 x + 12 = 0

9 x^{2} - 6 x - 3 = 0

(x - 1)^{2} = - 49

What are the solutions to the equation 3x^2+6x-2=-2 ?
The solutions to the equation 3x^2+6x-2=-2 are x=0,x=-2
Find the zeros of 3x^2+6x-2=-2
The zeros of 3x^2+6x-2=-2 are x=0,x=-2