What are the solutions to the equation 12x^2-200x+600=0 ?

The solutions to the equation 12x^2-200x+600=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3

Find the zeros of 12x^2-200x+600=0

The zeros of 12x^2-200x+600=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3

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12 x^{2} - 200 x + 600 = 0

x = \frac{5 ( 5 + 7 )}{3}, x = \frac{5 ( 5 - 7 )}{3}

Solution steps

12 x^{2} - 200 x + 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 12 \cdot 600}{2 \cdot 12}

(- 200)^{2} - 4 \cdot 12 \cdot 600 = 407

x_{1, 2} = \frac{- ( - 200 ) \pm 40 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 40 7}{2 \cdot 12}, x_{2} = \frac{- ( - 200 ) - 40 7}{2 \cdot 12}

x = \frac{- ( - 200 ) + 40 7}{2 \cdot 12} : \frac{5 ( 5 + 7 )}{3}

x = \frac{- ( - 200 ) - 40 7}{2 \cdot 12} : \frac{5 ( 5 - 7 )}{3}

The solutions to the quadratic equation are:

x = \frac{5 ( 5 + 7 )}{3}, x = \frac{5 ( 5 - 7 )}{3}

x^{2} + 6 x - 3 = 0

x^{2} + 7 x + 12 = 0

9 x^{2} - 6 x - 3 = 0

(x - 1)^{2} = - 49

m^{2} + 4 m - 9 = 0

What are the solutions to the equation 12x^2-200x+600=0 ?
The solutions to the equation 12x^2-200x+600=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3
Find the zeros of 12x^2-200x+600=0
The zeros of 12x^2-200x+600=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3