What are the solutions to the equation 2r^2+r-1=0 ?

The solutions to the equation 2r^2+r-1=0 are r= 1/2 ,r=-1

Find the zeros of 2r^2+r-1=0

The zeros of 2r^2+r-1=0 are r= 1/2 ,r=-1

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2 r^{2} + r - 1 = 0

r = \frac{1}{2}, r = - 1

Decimal Notation

r = 0.5, r = - 1

Solution steps

2 r^{2} + r - 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 1) = 3

r_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- 1 + 3}{2 \cdot 2}, r_{2} = \frac{- 1 - 3}{2 \cdot 2}

r = \frac{- 1 + 3}{2 \cdot 2} : \frac{1}{2}

r = \frac{- 1 - 3}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

r = \frac{1}{2}, r = - 1

x^{2} + 4 a x = - 3 a^{2}

x^{2} - 5 x + 36 = 0

16 (5 x - 6)^{2} - 41 = - 37

(x - 3) (x - 1) = 15

4 n^{2} - 9 n + 5 = 0

What are the solutions to the equation 2r^2+r-1=0 ?
The solutions to the equation 2r^2+r-1=0 are r= 1/2 ,r=-1
Find the zeros of 2r^2+r-1=0
The zeros of 2r^2+r-1=0 are r= 1/2 ,r=-1