What are the solutions to the equation 5x^2+17x-12=0 ?

The solutions to the equation 5x^2+17x-12=0 are x= 3/5 ,x=-4

Find the zeros of 5x^2+17x-12=0

The zeros of 5x^2+17x-12=0 are x= 3/5 ,x=-4

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5 x^{2} + 17 x - 12 = 0

x = \frac{3}{5}, x = - 4

Solution steps

5 x^{2} + 17 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

1 7^{2} - 4 \cdot 5 (- 12) = 23

x_{1, 2} = \frac{- 17 \pm 23}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 17 + 23}{2 \cdot 5}, x_{2} = \frac{- 17 - 23}{2 \cdot 5}

x = \frac{- 17 + 23}{2 \cdot 5} : \frac{3}{5}

x = \frac{- 17 - 23}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - 4

7 x^{2} - 16 = 0

2 x^{2} + 9 + 3 x = 5 x

x^{2} - 3 x + 20 = 0

x, x^{2} + y^{2} + z^{2} = 0

4 x^{2} - 16 x - 3

What are the solutions to the equation 5x^2+17x-12=0 ?
The solutions to the equation 5x^2+17x-12=0 are x= 3/5 ,x=-4
Find the zeros of 5x^2+17x-12=0
The zeros of 5x^2+17x-12=0 are x= 3/5 ,x=-4