What are the solutions to the equation 7x^2-16=0 ?

The solutions to the equation 7x^2-16=0 are x= 4/(sqrt(7)),x=-4/(sqrt(7))

Find the zeros of 7x^2-16=0

The zeros of 7x^2-16=0 are x= 4/(sqrt(7)),x=-4/(sqrt(7))

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7 x^{2} - 16 = 0

x = \frac{4}{7}, x = - \frac{4}{7}

Solution steps

7 x^{2} - 16 = 0

Move

16

to the right side

7 x^{2} = 16

Divide both sides by

7

x^{2} = \frac{16}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{7}, x = - \frac{16}{7}

\frac{16}{7} = \frac{4}{7}

- \frac{16}{7} = - \frac{4}{7}

x = \frac{4}{7}, x = - \frac{4}{7}

2 x^{2} + 9 + 3 x = 5 x

x^{2} - 3 x + 20 = 0

x, x^{2} + y^{2} + z^{2} = 0

4 x^{2} - 16 x - 3

- 0.2 x^{2} + 8 x + 20 = - 2.4 x + 97.4

What are the solutions to the equation 7x^2-16=0 ?
The solutions to the equation 7x^2-16=0 are x= 4/(sqrt(7)),x=-4/(sqrt(7))
Find the zeros of 7x^2-16=0
The zeros of 7x^2-16=0 are x= 4/(sqrt(7)),x=-4/(sqrt(7))