What are the solutions to the equation y^2-2y+12=0 ?

The solutions to the equation y^2-2y+12=0 are y=1+sqrt(11)i,y=1-sqrt(11)i

Find the zeros of y^2-2y+12=0

The zeros of y^2-2y+12=0 are y=1+sqrt(11)i,y=1-sqrt(11)i

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y^{2} - 2 y + 12 = 0

y = 1 + 11 i, y = 1 - 11 i

Solution steps

y^{2} - 2 y + 12 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 12 : 211 i

y_{1, 2} = \frac{- ( - 2 ) \pm 2 11 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 1} : 1 + 11 i

y = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 1} : 1 - 11 i

The solutions to the quadratic equation are:

y = 1 + 11 i, y = 1 - 11 i

2 x^{2} = 8 x + 64

x^{2} + 4 x - 36 = 0

2 x^{2} - 4 x + 3

(x + 2)^{2} + 3 (x + 1) (x + 4) = (x - 3) (x + 3) - 1

8 x^{2} - 22 x + 15 = 0

What are the solutions to the equation y^2-2y+12=0 ?
The solutions to the equation y^2-2y+12=0 are y=1+sqrt(11)i,y=1-sqrt(11)i
Find the zeros of y^2-2y+12=0
The zeros of y^2-2y+12=0 are y=1+sqrt(11)i,y=1-sqrt(11)i