What are the solutions to the equation factor 4x^2-12x+9=0 ?

The solutions to the equation factor 4x^2-12x+9=0 are x= 3/2

Find the zeros of factor 4x^2-12x+9=0

The zeros of factor 4x^2-12x+9=0 are x= 3/2

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4 x^{2} - 12 x + 9 = 0

x = \frac{3}{2}

Solution steps

4 x^{2} - 12 x + 9 = 0

Factor

4 x^{2} - 12 x + 9 : (2 x - 3)^{2}

(2 x - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

5^{2} + b^{2} = 9^{2}

3 y^{2} - 5 y + 2 = 0

r^{2} - r - 1 = 0

x^{2} - x = 9

3 x^{2} + x + 7 = x^{2} + 10

What are the solutions to the equation factor 4x^2-12x+9=0 ?
The solutions to the equation factor 4x^2-12x+9=0 are x= 3/2
Find the zeros of factor 4x^2-12x+9=0
The zeros of factor 4x^2-12x+9=0 are x= 3/2