What are the solutions to the equation 5^2+b^2=9^2 ?

The solutions to the equation 5^2+b^2=9^2 are b=2sqrt(14),b=-2sqrt(14)

Find the zeros of 5^2+b^2=9^2

The zeros of 5^2+b^2=9^2 are b=2sqrt(14),b=-2sqrt(14)

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5^{2} + b^{2} = 9^{2}

b = 214, b = - 214

Decimal Notation

b = 7.48331 \dots, b = - 7.48331 \dots

Solution steps

5^{2} + b^{2} = 9^{2}

Move

5^{2}

to the right side

b^{2} = 56

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 56, b = - 56

56 = 214

- 56 = - 214

b = 214, b = - 214

3 y^{2} - 5 y + 2 = 0

r^{2} - r - 1 = 0

x^{2} - x = 9

3 x^{2} + x + 7 = x^{2} + 10

4 x^{2} = - 1

What are the solutions to the equation 5^2+b^2=9^2 ?
The solutions to the equation 5^2+b^2=9^2 are b=2sqrt(14),b=-2sqrt(14)
Find the zeros of 5^2+b^2=9^2
The zeros of 5^2+b^2=9^2 are b=2sqrt(14),b=-2sqrt(14)