What are the solutions to the equation 6x^2-3x-3=0 ?

The solutions to the equation 6x^2-3x-3=0 are x=1,x=-1/2

Find the zeros of 6x^2-3x-3=0

The zeros of 6x^2-3x-3=0 are x=1,x=-1/2

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6 x^{2} - 3 x - 3 = 0

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

6 x^{2} - 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 3)^{2} - 4 \cdot 6 (- 3) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 6}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 6}

x = \frac{- ( - 3 ) + 9}{2 \cdot 6} : 1

x = \frac{- ( - 3 ) - 9}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

3 x^{2} - 2 x - 20 = 0

(x + 8)^{2} = 81

2 x^{2} + x - 105 = 0

- x^{2} + 12 = x

3 x^{2} - 2 x - 2 = - 1

What are the solutions to the equation 6x^2-3x-3=0 ?
The solutions to the equation 6x^2-3x-3=0 are x=1,x=-1/2
Find the zeros of 6x^2-3x-3=0
The zeros of 6x^2-3x-3=0 are x=1,x=-1/2