What are the solutions to the equation 3x^2-2x-20=0 ?

The solutions to the equation 3x^2-2x-20=0 are x=(1+sqrt(61))/3 ,x=(1-sqrt(61))/3

Find the zeros of 3x^2-2x-20=0

The zeros of 3x^2-2x-20=0 are x=(1+sqrt(61))/3 ,x=(1-sqrt(61))/3

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3 x^{2} - 2 x - 20 = 0

x = \frac{1 + 61}{3}, x = \frac{1 - 61}{3}

Decimal Notation

x = 2.93674 \dots, x = - 2.27008 \dots

Solution steps

3 x^{2} - 2 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 20) = 261

x_{1, 2} = \frac{- ( - 2 ) \pm 2 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 61}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 61}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 61}{2 \cdot 3} : \frac{1 + 61}{3}

x = \frac{- ( - 2 ) - 2 61}{2 \cdot 3} : \frac{1 - 61}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 61}{3}, x = \frac{1 - 61}{3}

(x + 8)^{2} = 81

2 x^{2} + x - 105 = 0

- x^{2} + 12 = x

3 x^{2} - 2 x - 2 = - 1

x^{2} + (n + 1) x + n = 0

What are the solutions to the equation 3x^2-2x-20=0 ?
The solutions to the equation 3x^2-2x-20=0 are x=(1+sqrt(61))/3 ,x=(1-sqrt(61))/3
Find the zeros of 3x^2-2x-20=0
The zeros of 3x^2-2x-20=0 are x=(1+sqrt(61))/3 ,x=(1-sqrt(61))/3