What are the solutions to the equation (x-2)(x+2)=11x-4 ?

The solutions to the equation (x-2)(x+2)=11x-4 are x=11,x=0

Find the zeros of (x-2)(x+2)=11x-4

The zeros of (x-2)(x+2)=11x-4 are x=11,x=0

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(x - 2) (x + 2) = 11 x - 4

x = 11, x = 0

Solution steps

(x - 2) (x + 2) = 11 x - 4

Expand

(x - 2) (x + 2) : x^{2} - 4

x^{2} - 4 = 11 x - 4

Move

4

to the left side

x^{2} = 11 x

Move

11 x

to the left side

x^{2} - 11 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 0 = 11

x_{1, 2} = \frac{- ( - 11 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 11}{2 \cdot 1}

x = \frac{- ( - 11 ) + 11}{2 \cdot 1} : 11

x = \frac{- ( - 11 ) - 11}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 11, x = 0

12 x^{2} - 180 x + 500 = 0

3 p^{2} + 4 p = 8

34 = 105 t - 16 t^{2}

x, x^{2} - x - 1 = 0

z (z + 7) = 30

What are the solutions to the equation (x-2)(x+2)=11x-4 ?
The solutions to the equation (x-2)(x+2)=11x-4 are x=11,x=0
Find the zeros of (x-2)(x+2)=11x-4
The zeros of (x-2)(x+2)=11x-4 are x=11,x=0