What are the solutions to the equation 4a^2+6a-6=-3 ?

The solutions to the equation 4a^2+6a-6=-3 are a=(-3+sqrt(21))/4 ,a=-(3+sqrt(21))/4

Find the zeros of 4a^2+6a-6=-3

The zeros of 4a^2+6a-6=-3 are a=(-3+sqrt(21))/4 ,a=-(3+sqrt(21))/4

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4 a^{2} + 6 a - 6 = - 3

a = \frac{- 3 + 21}{4}, a = - \frac{3 + 21}{4}

Decimal Notation

a = 0.39564 \dots, a = - 1.89564 \dots

Solution steps

4 a^{2} + 6 a - 6 = - 3

Move

3

to the left side

4 a^{2} + 6 a - 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 3) = 221

a_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- 6 + 2 21}{2 \cdot 4}, a_{2} = \frac{- 6 - 2 21}{2 \cdot 4}

a = \frac{- 6 + 2 21}{2 \cdot 4} : \frac{- 3 + 21}{4}

a = \frac{- 6 - 2 21}{2 \cdot 4} : - \frac{3 + 21}{4}

The solutions to the quadratic equation are:

a = \frac{- 3 + 21}{4}, a = - \frac{3 + 21}{4}

(x - 2) (x + 2) = 11 x - 4

12 x^{2} - 180 x + 500 = 0

3 p^{2} + 4 p = 8

34 = 105 t - 16 t^{2}

x, x^{2} - x - 1 = 0

What are the solutions to the equation 4a^2+6a-6=-3 ?
The solutions to the equation 4a^2+6a-6=-3 are a=(-3+sqrt(21))/4 ,a=-(3+sqrt(21))/4
Find the zeros of 4a^2+6a-6=-3
The zeros of 4a^2+6a-6=-3 are a=(-3+sqrt(21))/4 ,a=-(3+sqrt(21))/4