What are the solutions to the equation 34=105t-16t^2 ?

The solutions to the equation 34=105t-16t^2 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)

Find the zeros of 34=105t-16t^2

The zeros of 34=105t-16t^2 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)

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34 = 105 t - 16 t^{2}

t = \frac{105 - 8849}{32}, t = \frac{105 + 8849}{32}

Decimal Notation

t = 0.34158 \dots, t = 6.22091 \dots

Solution steps

34 = 105 t - 16 t^{2}

Switch sides

105 t - 16 t^{2} = 34

Move

34

to the left side

105 t - 16 t^{2} - 34 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 105 t - 34 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 105 \pm 10 5 ^{2} - 4 ( - 16 ) ( - 34 )}{2 ( - 16 )}

10 5^{2} - 4 (- 16) (- 34) = 8849

t_{1, 2} = \frac{- 105 \pm 8849}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 105 + 8849}{2 ( - 16 )}, t_{2} = \frac{- 105 - 8849}{2 ( - 16 )}

t = \frac{- 105 + 8849}{2 ( - 16 )} : \frac{105 - 8849}{32}

t = \frac{- 105 - 8849}{2 ( - 16 )} : \frac{105 + 8849}{32}

The solutions to the quadratic equation are:

t = \frac{105 - 8849}{32}, t = \frac{105 + 8849}{32}

x, x^{2} - x - 1 = 0

z (z + 7) = 30

m^{2} - 8 m + 15 = 0

4 + 8 + 12 + 4 n = 2 n (n + 1)

12 x^{2} + 9 x - 2 = - 17

What are the solutions to the equation 34=105t-16t^2 ?
The solutions to the equation 34=105t-16t^2 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)
Find the zeros of 34=105t-16t^2
The zeros of 34=105t-16t^2 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)