What are the solutions to the equation 3p^2+4p=8 ?

The solutions to the equation 3p^2+4p=8 are p=(2(sqrt(7)-1))/3 ,p=-(2(1+sqrt(7)))/3

Find the zeros of 3p^2+4p=8

The zeros of 3p^2+4p=8 are p=(2(sqrt(7)-1))/3 ,p=-(2(1+sqrt(7)))/3

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3 p^{2} + 4 p = 8

p = \frac{2 ( 7 - 1 )}{3}, p = - \frac{2 ( 1 + 7 )}{3}

Decimal Notation

p = 1.09716 \dots, p = - 2.43050 \dots

Solution steps

3 p^{2} + 4 p = 8

Move

8

to the left side

3 p^{2} + 4 p - 8 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 8) = 47

p_{1, 2} = \frac{- 4 \pm 4 7}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- 4 + 4 7}{2 \cdot 3}, p_{2} = \frac{- 4 - 4 7}{2 \cdot 3}

p = \frac{- 4 + 4 7}{2 \cdot 3} : \frac{2 ( 7 - 1 )}{3}

p = \frac{- 4 - 4 7}{2 \cdot 3} : - \frac{2 ( 1 + 7 )}{3}

The solutions to the quadratic equation are:

p = \frac{2 ( 7 - 1 )}{3}, p = - \frac{2 ( 1 + 7 )}{3}

34 = 105 t - 16 t^{2}

x, x^{2} - x - 1 = 0

z (z + 7) = 30

m^{2} - 8 m + 15 = 0

4 + 8 + 12 + 4 n = 2 n (n + 1)

What are the solutions to the equation 3p^2+4p=8 ?
The solutions to the equation 3p^2+4p=8 are p=(2(sqrt(7)-1))/3 ,p=-(2(1+sqrt(7)))/3
Find the zeros of 3p^2+4p=8
The zeros of 3p^2+4p=8 are p=(2(sqrt(7)-1))/3 ,p=-(2(1+sqrt(7)))/3