What are the solutions to the equation -3x^2+4x-1=0 ?

The solutions to the equation -3x^2+4x-1=0 are x= 1/3 ,x=1

Find the zeros of -3x^2+4x-1=0

The zeros of -3x^2+4x-1=0 are x= 1/3 ,x=1

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- 3 x^{2} + 4 x - 1 = 0

x = \frac{1}{3}, x = 1

Decimal Notation

x = 0.33333 \dots, x = 1

Solution steps

- 3 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

4^{2} - 4 (- 3) (- 1) = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 ( - 3 )}, x_{2} = \frac{- 4 - 2}{2 ( - 3 )}

x = \frac{- 4 + 2}{2 ( - 3 )} : \frac{1}{3}

x = \frac{- 4 - 2}{2 ( - 3 )} : 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = 1

y (y + 6) = 2

x^{2} + 1 = - 8

2 x^{2} + 4 x - 10 = 0

\frac{( x + 2 ) ^{2}}{5} + \frac{( x - 2 ) ^{2}}{3} = \frac{16}{3}

x^{2} - x - 1

What are the solutions to the equation -3x^2+4x-1=0 ?
The solutions to the equation -3x^2+4x-1=0 are x= 1/3 ,x=1
Find the zeros of -3x^2+4x-1=0
The zeros of -3x^2+4x-1=0 are x= 1/3 ,x=1