What are the solutions to the equation (x+3)^2+2(x+3)-8=0 ?

The solutions to the equation (x+3)^2+2(x+3)-8=0 are x=-1,x=-7

Find the zeros of (x+3)^2+2(x+3)-8=0

The zeros of (x+3)^2+2(x+3)-8=0 are x=-1,x=-7

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(x + 3)^{2} + 2 (x + 3) - 8 = 0

x = - 1, x = - 7

Solution steps

(x + 3)^{2} + 2 (x + 3) - 8 = 0

Expand

(x + 3)^{2} + 2 (x + 3) - 8 : x^{2} + 8 x + 7

x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 6}{2 \cdot 1}

x = \frac{- 8 + 6}{2 \cdot 1} : - 1

x = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

- 3 x^{2} + 5 x + 7 = 0

q^{2} + 20 q = - 104

x^{2} - 27 x + 65 = - 13 x

x^{2} + 14 x + 30 = 0

9 x^{2} + 7 x - 4 = 0

What are the solutions to the equation (x+3)^2+2(x+3)-8=0 ?
The solutions to the equation (x+3)^2+2(x+3)-8=0 are x=-1,x=-7
Find the zeros of (x+3)^2+2(x+3)-8=0
The zeros of (x+3)^2+2(x+3)-8=0 are x=-1,x=-7