What are the solutions to the equation 3s-2s^2= 3/2 ?

The solutions to the equation 3s-2s^2= 3/2 are s= 3/4-i(sqrt(3))/4 ,s= 3/4+i(sqrt(3))/4

Find the zeros of 3s-2s^2= 3/2

The zeros of 3s-2s^2= 3/2 are s= 3/4-i(sqrt(3))/4 ,s= 3/4+i(sqrt(3))/4

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3 s - 2 s^{2} = \frac{3}{2}

s = \frac{3}{4} - i \frac{3}{4}, s = \frac{3}{4} + i \frac{3}{4}

Solution steps

3 s - 2 s^{2} = \frac{3}{2}

Multiply both sides by

2

6 s - 4 s^{2} = 3

Move

3

to the left side

6 s - 4 s^{2} - 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 s^{2} + 6 s - 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

Simplify

6^{2} - 4 (- 4) (- 3) : 23 i

s_{1, 2} = \frac{- 6 \pm 2 3 i}{2 ( - 4 )}

Separate the solutions

s_{1} = \frac{- 6 + 2 3 i}{2 ( - 4 )}, s_{2} = \frac{- 6 - 2 3 i}{2 ( - 4 )}

s = \frac{- 6 + 2 3 i}{2 ( - 4 )} : \frac{3}{4} - i \frac{3}{4}

s = \frac{- 6 - 2 3 i}{2 ( - 4 )} : \frac{3}{4} + i \frac{3}{4}

The solutions to the quadratic equation are:

s = \frac{3}{4} - i \frac{3}{4}, s = \frac{3}{4} + i \frac{3}{4}

- 48 x^{2} - 36 x - 6 = 0

j (x) = - 4 x^{2} - 2 x + 2

x^{2} + x - 0.5 = 0

x^{2} - 4 x - 21 = 0

- 2 x^{2} + 9 x + 29 = - 6

What are the solutions to the equation 3s-2s^2= 3/2 ?
The solutions to the equation 3s-2s^2= 3/2 are s= 3/4-i(sqrt(3))/4 ,s= 3/4+i(sqrt(3))/4
Find the zeros of 3s-2s^2= 3/2
The zeros of 3s-2s^2= 3/2 are s= 3/4-i(sqrt(3))/4 ,s= 3/4+i(sqrt(3))/4