What are the solutions to the equation m^2+8m+25=0 ?

The solutions to the equation m^2+8m+25=0 are m=-4+3i,m=-4-3i

Find the zeros of m^2+8m+25=0

The zeros of m^2+8m+25=0 are m=-4+3i,m=-4-3i

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m^{2} + 8 m + 25 = 0

m = - 4 + 3 i, m = - 4 - 3 i

Solution steps

m^{2} + 8 m + 25 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 25 : 6 i

m_{1, 2} = \frac{- 8 \pm 6 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 6 i}{2 \cdot 1}, m_{2} = \frac{- 8 - 6 i}{2 \cdot 1}

m = \frac{- 8 + 6 i}{2 \cdot 1} : - 4 + 3 i

m = \frac{- 8 - 6 i}{2 \cdot 1} : - 4 - 3 i

The solutions to the quadratic equation are:

m = - 4 + 3 i, m = - 4 - 3 i

\frac{4 x ^{2} - 4 x}{3} - x = x^{2} - \frac{3 x + 4}{3}

x^{2} - 2 x - 25 = 0

q^{2} + 8 q + 16 = - 5 q^{2} + 6 q + 416

2 x^{2} - 7 x - 11 = 0

5 x^{2} + 3 = x

What are the solutions to the equation m^2+8m+25=0 ?
The solutions to the equation m^2+8m+25=0 are m=-4+3i,m=-4-3i
Find the zeros of m^2+8m+25=0
The zeros of m^2+8m+25=0 are m=-4+3i,m=-4-3i