What are the solutions to the equation (x+2)^2+(x-1)^2=0 ?

The solutions to the equation (x+2)^2+(x-1)^2=0 are x=-1/2+i 3/2 ,x=-1/2-i 3/2

Find the zeros of (x+2)^2+(x-1)^2=0

The zeros of (x+2)^2+(x-1)^2=0 are x=-1/2+i 3/2 ,x=-1/2-i 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2)^{2} + (x - 1)^{2} = 0

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

(x + 2)^{2} + (x - 1)^{2} = 0

Expand

(x + 2)^{2} + (x - 1)^{2} : 2 x^{2} + 2 x + 5

2 x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

2^{2} - 4 \cdot 2 \cdot 5 : 6 i

x_{1, 2} = \frac{- 2 \pm 6 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 6 i}{2 \cdot 2}, x_{2} = \frac{- 2 - 6 i}{2 \cdot 2}

x = \frac{- 2 + 6 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{3}{2}

x = \frac{- 2 - 6 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

x, x^{2} - 2 x y + y^{2} - x = 0

\frac{x ^{2} - 5}{3} + \frac{4 x ^{2} - 1}{5} - \frac{14 x ^{2} - 1}{15} = 0

x, x^{2} + y^{2} - 8 x + 6 y + 29 = 0

4 m^{2} + 12 m + 9 = 0

5 x^{2} + 20 x + 20 = 0

What are the solutions to the equation (x+2)^2+(x-1)^2=0 ?
The solutions to the equation (x+2)^2+(x-1)^2=0 are x=-1/2+i 3/2 ,x=-1/2-i 3/2
Find the zeros of (x+2)^2+(x-1)^2=0
The zeros of (x+2)^2+(x-1)^2=0 are x=-1/2+i 3/2 ,x=-1/2-i 3/2