What are the solutions to the equation 9u^2-11u+7=0 ?

The solutions to the equation 9u^2-11u+7=0 are u= 11/18+i(sqrt(131))/(18),u= 11/18-i(sqrt(131))/(18)

Find the zeros of 9u^2-11u+7=0

The zeros of 9u^2-11u+7=0 are u= 11/18+i(sqrt(131))/(18),u= 11/18-i(sqrt(131))/(18)

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9 u^{2} - 11 u + 7 = 0

u = \frac{11}{18} + i \frac{131}{18}, u = \frac{11}{18} - i \frac{131}{18}

Solution steps

9 u^{2} - 11 u + 7 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 9 \cdot 7}{2 \cdot 9}

Simplify

(- 11)^{2} - 4 \cdot 9 \cdot 7 : 131 i

u_{1, 2} = \frac{- ( - 11 ) \pm 131 i}{2 \cdot 9}

Separate the solutions

u_{1} = \frac{- ( - 11 ) + 131 i}{2 \cdot 9}, u_{2} = \frac{- ( - 11 ) - 131 i}{2 \cdot 9}

u = \frac{- ( - 11 ) + 131 i}{2 \cdot 9} : \frac{11}{18} + i \frac{131}{18}

u = \frac{- ( - 11 ) - 131 i}{2 \cdot 9} : \frac{11}{18} - i \frac{131}{18}

The solutions to the quadratic equation are:

u = \frac{11}{18} + i \frac{131}{18}, u = \frac{11}{18} - i \frac{131}{18}

2 x^{2} - 2 = - 25

6^{2} + 2^{2} = x^{2}

y^{2} + 11 y + 10 = 0

24 x = - 48 - 3 x^{2}

x^{2} + 9^{2} = 1 0^{2}

What are the solutions to the equation 9u^2-11u+7=0 ?
The solutions to the equation 9u^2-11u+7=0 are u= 11/18+i(sqrt(131))/(18),u= 11/18-i(sqrt(131))/(18)
Find the zeros of 9u^2-11u+7=0
The zeros of 9u^2-11u+7=0 are u= 11/18+i(sqrt(131))/(18),u= 11/18-i(sqrt(131))/(18)