What are the solutions to the equation x^2+2^2=3^2 ?

The solutions to the equation x^2+2^2=3^2 are x=sqrt(5),x=-sqrt(5)

Find the zeros of x^2+2^2=3^2

The zeros of x^2+2^2=3^2 are x=sqrt(5),x=-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2^{2} = 3^{2}

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

x^{2} + 2^{2} = 3^{2}

Move

2^{2}

to the right side

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

(3 x - 1) (x - 1) = 96

- 5 x^{2} + 6 x + 14 = - 5

5 x^{2} + 6 x + 9 = 0

(x + 4)^{2} = 28

(x + 4)^{2} = 20

What are the solutions to the equation x^2+2^2=3^2 ?
The solutions to the equation x^2+2^2=3^2 are x=sqrt(5),x=-sqrt(5)
Find the zeros of x^2+2^2=3^2
The zeros of x^2+2^2=3^2 are x=sqrt(5),x=-sqrt(5)